At what rate percent will a sum of ₹ 4000 yield ₹ 1324 as compound interest in three years?

at what rate percent will a sum of rupees 4000 1324 as compound interest in 3 years at select the right your BF given that uses of principal amount that is T is equals to 4000 rupees tight and it is also given that read 1324 as compound interest in this means we have compound interest amount as this is equals to 1324 and it is also given that in three years that means we are having time that is represented by a small team this is equals to 3 tight so we can see that that amount that is which is equals to nearest e plus we can write 4000 plus 1324 we can see that amount 5324 right now we know that there is a formula that is is equals to 2 into 1 + R 100

party wear by having the value of a that is 532484 5324 and the sequel to the value of P that is given as 4000 INR to 1 + r100 old is the party and 80s of TV having 33 you know if this were then we can write 5324 / 4000 and this is equals to 1 + R by hundred old is 23 now if salt is then here we can write it is 13311 / 2003 we divide both numerator and denominator by 4 then we can add this 133 1050 equals to 1 + r100 whole cube now here we can also write this as 11 b n whole cube so we compare

this one with this then we can see that we're having 11 b n is equal to 1 + R 100 right from here we can see that rr100 is equal to 11 b n -1 which is equals to 1 by 10 from here we can see that here this 10-10 get cancelled with this and we can see that our are is equals to 10% and hence we can see that this the final answer thank you

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Solution

Given that principal = Rs.4000And C I = Rs.1324Amount = Principal + C.IA = 4000 + 1324 .A = Rs. 5324 let the rate of interest = r%. Given time = 3 yearsAmount= P(1+R100)n⇒ 5324 = 4000(1+r100)3​​​​​​​⇒ 53244000 = (1+r100)3​​​​​​​​​​​​​​​​​​​​​⇒ 13311000 = (1+r100)3​​​​​​​​​​​​​​​​​​​​​​​​​​​​ ⇒ 113103 = (1+r100)3​​​​​​​​​​​​​​​​​​​​​ [ cube root on both sides]⇒ 1110 = (1+r100)​​​​​​​​​​​​​​​​​​​​​⇒ 1110 - 1 = r100​​​​​​​​​​​​​​​​​​​​​⇒ 110 = r100∴ r =10%Hence the rate of interest is 10%.

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