Directions: Kindly read the questions carefully and answer the questions given below.
1
What would be the compound interest obtained on an amount of Rs. 4,800 at the rate of 5 p.c.p.a after 3 years?
A. Rs 623.5
B. Rs 756.5
C. Rs 817.8
D. Rs 448.7
2
The difference between compound interest and simple interest at the same rate of interest R percent per annum on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the value of R?
A. 8%
B. 10%
C. 12%
D. Can't be determined due to insufficient data
3
There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest on Rs. 12000 after 3 years at the same rate of interest?
A. Rs. 2160
B. Rs. 3120
C. Rs. 3972
D. Rs. 6240
4
An automobile financier claims to be lending money at simple interest, but he includes the interest every six months for calculating the principal. If he is charging an interest at the rate of 10%, the effective rate interest becomes
A. 10.25%
B. 10.5%
C. 10.75%
D. 11%
5
The certain sum will amount to Rs 12,100 in 2 years at 10% per annum of compound interest, interest being compounded annually. The sum is
A. Rs. 10,000
B. Rs. 8,000
C. Rs. 6,000
D. Rs. 12,000
6
The difference between C.I. and S.I. on Rs. 6000 for 1 year at 20% per annum recorded half yearly is:
A. 45
B. 55
C. 60
D. 58
7
Divide Rs. 2602 between X and Y so that the amount of X after 7 yr is equal to the amount of Y after 9 yr, the interest being compounded at 4% pa.
A. Rs. 1352, Rs. 1250
B. Rs. 1252, Rs. 1350
C. Rs. 1400, Rs. 1202
D. Rs. 1052, Rs. 1500
8
A man borrows Rs. 5100 to be paid back with compound interest at the rate of 4% pa by the end of 2 yr in two equal yearly investments. How much will each installment be?
A. ₹ 2704
B. ₹ 2800
C. ₹ 3000
D. ₹ 2500
9
Sushmita invests a certain sum of money for 3 years at 10% pa at simple interest rate. The SI accrued is half the CI on Rs. 10000 for 2 years at 10% pa. Find the sum placed on simple interest?
A. ₹ 3200
B. ₹ 3500
C. ₹ 3000
D. ₹ 1050
10 What is the CI accrued on an amount of Rs. 16000 at the rate of 5% per annum at the end of 2 years?
A. ₹ 1640
B. ₹ 1832
C. ₹ 1540
D. ₹ 1400
Question No. 1
Correct Option: B
Explanation:
P = 4800, T = 3 years, R = 5%
By the net% effect we would calculate the effective compound rate of interest for 3 years = 15.76% (Refer to sub-details)
Therefore, CI = 15.76% of 4800
CI = | 15.76 × 4800 | = ₹ 756.5 |
100 |
_________________________________________________________________
Sub-details:
Calculation of effective compound rate of interest for 3 years will be as follows.
For the first 2 years, let's apply the net% effect.
Here, x = y = 5%
Net% effect = x + y = | xy | |
100 |
= 5 + 5 + | 5 × 5 | = 10 + 0.25 = 10.25% |
100 |
Now let's take this 10.25% as x and 5% as y for the calculation of 3rd year.
= 10.25 + 5 + | 10.25 × 5 | = 15.25 + .51 = 15.76% |
100 |
________________________________________________
Traditional Method:
CI = 4800 | [( | 1 + | 5 | ) | 3 | – 1 | ] |
100 |
= 4800 | [ | 21 × 21 × 21 – 20 × 20 × 20 | ] |
20 × 20 × 20 |
= 4800 × | ( | 9261 – 8000 | ) | ⇒ 4800 × | 1261 | = ₹ 756.6. |
20 × 20 × 20 | 8000 |
Hence, option B is correct.
Question No. 2
Correct Option: A
Explanation:
Smart Approach:
To solve this question, we can apply a short trick approach
Sum = | Difference × 1002 |
r2 |
Given,
Sum (Amount) = 15000, Difference = 96, r = ?
By the short trick approach, we get
15000 = | 96 × 1002 | ⇒ r2 = | 96 × 1002 | ⇒ r2 = 64 ⇒ r = 8% |
r2 | 15000 |
Traditional Approach:
As per the information, we get the eqn.
CI for 2 years – SI for 2 years = 96
[ | 15000 × | ( | 1 + | R | ) | 2 | – 15000 | ] | – | ( | 15000 × R × 2 | ) | = 96 |
100 | 100 |
⇒ 15000 | [( | 1 + | R | ) | 2 | – 1 – | 2R | ] | = 96 |
100 | 100 |
⇒ 15000 | [ | (100 + R2) – 10000 – 200 R | ] | = 96 |
10000 |
⇒ R2 = | 96 × 2 | = 64 ⇒ R = 8. |
3 |
∴ Rate = 8%
Hence, option A is correct.
Question No. 3
Correct Option: C
Explanation:
Since increase in interest in 6 years = 60%
Therefore, increase in interest in 1 year = 10% (Rate of interest)
Now, P = 12000, T = 3 years & R = 10% p.a.
By the net% effect we would calculate the effective compound rate of interest for 3 years = 33.1% (Refer to sub-details)
Therefore, CI = 33.1% of 12000
CI = | 33.1 × 12000 | = ₹ 3972. |
100 |
_________________________________________________________________
Sub-details:
Calculation of effective compound rate of interest for 3 years will be as follows.
For the first two years, let's apply the net% effect.
Here, x = y = 10%
Net% effect = x + y = | xy | |
100 |
= 10 + 10 + | 10 × 10 | = 21% |
100 |
Now let's take this 21% as x and 10% as y for the calculation of 3rd year.
= 21 + 10 + | 21 × 10 | = 33.1% |
100 |
Hence, option C is correct.
Question No. 4
Correct Option: A
Explanation:
Yearly rate of interest = 10%
Rate of interest charged on half yearly basis = 5%
It's given that the financier charges interest on half yearly basis. Hence, he actually charges Compound Interst and not Simple Interest.
Therefore, applying the net% effect formula for effective rate of compound interest for 2 half years (1 year = 2 half years), we get
Net% effect = x + y + | xy | |
100 |
x = y = 5%
Net% effect = 5 + 5 + | 5 × 5 | = 10 + 0.25 = 10.25% |
100 |
Hence, option A is correct.
Question No. 5
Correct Option: A
Explanation:
To solve this question, we can apply a net% effect formula
Net% effect = x + y + | xy | % |
100 |
x = y = 10%
= 10 + 10 + | 10 × 10 | = 21% |
100 |
Now, Amount (P + CI) = (100 + 21)% = 121% | ≡ | ₹ 12100 |
By the cross multiplication, we get
x = | 12100 × 100 | = ₹ 10000. |
121 |
__________________________________________________________
Traditional Method:
Given,
Amount = 12,100; r = 10%, t = 2 yrs
Amount = | P | [ | 1 + | r | ] | t |
100 |
12100 = | P | [ | 1 + | 10 | ] | 2 |
100 |
⇒ 12100 = | P | [ | 11 | ] | 2 | ⇒ 12100 = P × | 11 | × | 11 |
10 | 10 | 10 |
⇒ P = ₹ 10,000.
Hence, option A is correct.
Question No. 6
Correct Option: C
Explanation:
Method I:
To solve this question, we can apply a short trick approach
Sum = | Difference × (100)2 | |
r2 |
Sum = ₹ 6000, r = 20/2 = 10% (half yearly rate of interest), Differece = ?
By the short trick approach, we get
⇒ 6000 = | Difference × (100)2 |
102 |
⇒ Difference = | 6000 × 10 × 10 | = Rs. 60. |
100 × 100 |
____________________________________________________________
Method II:
We can solve it by applying the net% effect formula,
Rate % of SI for 1 yr (2 half years) at 10% pa (rate will be halved here) = 10 × 2 = 20%
Rate % of CI for 1 yr (2 half years) at 10% pa (rate will be halved here as well),
= 10 + 10 + | 10 × 10 | = 21% | |
100 |
% rate difference of CI and SI = 21% – 20 = 1%
Now, 1% of 6,000 = Rs. 60.
____________________________________________
Traditional Method:
S.I. for 1 year (calculated on half yearly basis)
= | 6000 × 10 × 2 | = 1200. |
100 |
C.I. for 1 year (calculated on half yearly basis)
⇒ 7260 – 6000 = 1260.
Difference = 1260 – 1200 = Rs. 60.
Hence, option C is correct.
Question No. 7
Correct Option: A
Explanation:
Let the first part = x.
Then, Second part = (2602 – x)
According to the question,
x |
| = (2602 – x) |
|
⇒ | = |
| ||||||||
|
⇒ 625x = (2602 – x) 676
⇒ 625x = 2602 × 676 – 676x
⇒ 1301x = 2602 × 676
⇒ x = 2 × 676 = 1352.
Hence, option A is correct.
Question No. 8
Correct Option: A
Explanation:
Let the installments be x. Then,
According to the question,
| A | ||||||||||||||
|
⇒ | 25x | + | 625x | = 5100 |
26 | 676 |
⇒ | 25x × 26 + 625x | = 5100 |
676 |
⇒ 650x + 625x = | 5100 × 676 |
⇒ x = | 5100 × 676 | = ₹ 2704 |
1275 |
Hence, option A is correct.
Question No. 9
Correct Option: B
Explanation:
Applyng the net% effect formula to calculate the net CI rate for 2 years, we get
= 10 + 10 + | 10 × 10 | = 21% | |
100 |
Now, 21% of 10000 = 2100
Sum of SI is half of CI = | 2100 | = 1050 |
2 |
As we know, Sum = | SI × 100 | ||
RT |
∴ Sum = | 1050 × 100 | = ₹ 3500 | |
3 × 10 |
Hence, option B is correct.
Question No. 10
Correct Option: A
Explanation:
To solve this question, we can apply the net% effect formula
Net% effect = x + y + | xy | % |
100 |
Here, x = y = 5% (because rate of interest is same for both the years)
By the net% effect, we get effective rate of interest
= 5 + 5 + | 5 × 5 | % = 10.25% | |
100 |
Therefore, 10.25% of 16000
= 10.25 × 160 = ₹ 1640
Hence, option A is correct.