If 10 coins are tossed in succession what is the probability that at least 3 will be heads

Solution : In tossing three coins, the sample space is given gy <br> `S = {"HHH, HHT, HTH, THH, HTT, THT, TTH, TTT"}.` <br> And, therefore, n(S) = 8. <br> (i) Let `E_(1)` = event of getting all heads. Then, <br> `E_(1) = {HHH}` and, therefore, `n(E_(1)) = 1.` <br> `therefore` P (getting all heads) `= P(E_(1)) = (n(E_(1)))/(n(S)) = 1/8.` <br> (ii) Let `E_(2)` = event of getting 2 heads. Then, <br> `E_(2) = {HHT, HTH, THH}` and, therefore, `n(E_(2)) = 3.` <br> `therefore` P (getting 2 heads) `= P(E_(2)) = (n(E_(2)))/(n(S)) = 3/8.` <br> (iii) Let `E_(3)` = event of getting 1 head. Then, <br> `E_(3) = {"HTT, THT, TTH" }` and, therefore, `n(E_(3)) = 3.` <br> `therefore` P (getting 1 head) `= P(E_(3)) = (n(E_(3)))/(n(S)) = 3/8.` <br> (iv) Let `E_(4)` = event of getting at least 1 heads. Then, <br> `E_(4) = {"HTT, THT, TTH, HHT, HTH, THH, HHH"}` and, therefore, `n(E_(4)) = 7.` <br> `therefore` P (getting at least 1 head) `= P(E_(4)) = (n(E_(4)))/(n(S)) = 7/8.` <br> (v) Let `E_(5)` = event of getting at least 2 heads. Then, <br> `E_(5) = {"HHT, HTH, THH, HHH"}` and, therefore, `n(E_(1)) = 1.` <br> `therefore` P (getting all heads) `= P(E_(5)) = (n(E_(5)))/(n(S)) = 4/8 = 1/2.`

Probability is a part of mathematics that deals with the possibility of happening of events. It is to forecast that what are the possible chances that the events will occur or the event will not occur. The probability as a number lies between 0 and 1 only and can also be written in the form of a percentage or fraction. The probability of likely event A is often written as P(A). Here P shows the possibility and A shows the happening of an event. Similarly, the probability of any event is often written as P(). When the end outcome of an event is not confirmed we use the probabilities of certain outcomes—how likely they occur or what are the chances of their occurring.

To understand probability more accurately we take an example as rolling a dice:

The possible outcomes are — 1, 2, 3, 4, 5, and 6.

The probability of getting any of the outcomes is 1/6. As the possibility of happening of an event is an equally likely event so there are same chances of getting any number in this case it is either 1/6 or 50/3%.

Formula of Probability

Probability of an event, P(A) = (Number of ways it can occur) ⁄ (Total number of outcomes)

Types of Events

  • Equally Likely Events: After rolling dice, the probability of getting any of the likely events is 1/6. As the event is an equally likely event so there is same possibility of getting any number in this case it is either 1/6 in fair dice rolling.
  • Complementary Events: There is a possibility of only two outcomes which is an event will occur or not. Like a person will play or not play, buying a laptop or not buying a laptop, etc. are examples of complementary events.

If a coin is tossed 7 times, what is the probability of getting 5 heads?

Solution:

Use the binomial distribution directly. Let us assume that the number of heads is represented by x  (where a result of heads is regarded as success) and in this case X = 5

Assuming that the coin is unbiased, you have a probability of success ‘p’(where p is considered as success) is 1/2 and the probability of failure ‘q’ is 1/2(where q is considered as failure). The number of trials is represented by the letter ’n’ and for this question n = 7.

Now just use the probability function for a binomial distribution:

P(X = x) = nCxpxqn-x

Using the information in the problem we get

P(X = 5) = (7C5)(1/2)5(1/2)2

= 21 × 1/32 × 1/4

= 21/128

Hence, the probability of flipping a coin 7 times and getting heads 5 times is 21/128.

Similar Questions

Question 1: What is the probability of flipping a coin 20 times and getting 5 heads?

Answer:

Each coin can either land on heads or on tails, 2 choices.  

(According to the binomial concept)

This gives us a total of 220 possibilities for flipping 20 coins.

Now, how many ways can we get 5 heads? This is 20 choose 5, or (20C5)  

This means our probability is (20C5)/220 = 15504⁄1048576 ≈ .01478

Question 2: What is the probability of 2 heads when 2 coins are tossed together?

Solution:

2 coin tosses. This means,

Total observations = 4(According to binomial concept)  

Required outcome → 2 Heads {H,H}

This can occur only ONCE!

Thus, required outcome = 1  

Probability (2 Heads) = (1⁄2)2 = 1/4

What is the probability of getting 3 heads when 10 coins are tossed?

So the probability of exactly 3 heads in 10 tosses is 1201024. Remark: The idea can be substantially generalized. If we toss a coin n times, and the probability of a head on any toss is p (which need not be equal to 1/2, the coin could be unfair), then the probability of exactly k heads is (nk)pk(1−p)n−k.

What is the probability of getting at least 3 head?

Answer: If you flip a coin 3 times the probability of getting 3 heads is 0.125. When you flip a coin 3 times, then all the possibe 8 outcomes are HHH, THH, HTH, HHT, TTH, THT, HTT, TTT.

What is the probability of tossing 3 heads in succession?

Answer: If a coin is tossed three times, the likelihood of obtaining three heads in a row is 1/8.

What is the probability of getting 3 heads out of 10 tries?

Probability of having any head is 1/2. Probability of having 3 heads is 3/10.

Toplist

Neuester Beitrag

Stichworte