What is the common difference between successive terms in the sequence 2 8, 14, 20, 26 6 4 4 6

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Maria B.

Algebra

8 months, 2 weeks ago

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What is the common difference between successive terms in the sequence? 0.36,0.26,0.16,0.06,-0.04,-014

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So what exactly is a sequence? A sequence is a list of border numbers. So for example My first number is 0.36. My second is 0.26. My third is 0.16 and so on and so forth. Now in a sequence I can have a pattern or I cannot have a pattern. Okay, so successive. What is successive? B kind of the same as consecutive? Or it means right next to each other. So what's the common difference? Common differences. The same thing as pattern? What's the pattern here? How do I get from the first term to the second term? Well it seems like what's that difference there? I could just subtract these two terms .36 -16. That's approximately -0.10 or 0.1. Is that the same pattern here? In -0.10 -0.10 rate. I could test this. And so with my common difference, fear my pattern, my pattern which is my common difference would be -0.10 or approximately 0.10.

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What is the common difference between the successive terms in the sequence 2 8 14 20 26?

The common difference is the difference between any two consecutive terms in an arithmetic sequence. 2, 8, 14, 20, 26 … = 2, (2 + 6), (8 + 6), (14 + 6), (20+ 6) … Therefore, the common difference is 6.

What is the common difference between successive terms in sequence 2 4 8?

Summary: The common ratio between successive terms in the sequence 2, -4, 8, -16, 32, -64,... is -2.

What is the common difference between successive terms in sequence?

A common difference is the difference between consecutive numbers in an arithematic sequence. To find it, simply subtract the first term from the second term, or the second from the third, or so on... See how each time we are adding 8 to get to the next term?

Which of the following sequences is an arithmetic sequence why 2 8 14 20 26?

This is an arithmetic sequence since there is a common difference between each term. In this case, adding 6 to the previous term in the sequence gives the next term. In other words, an=a1+d(n−1) a n = a 1 + d ( n - 1 ) .

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