Which is a possible turning point for the continuous function f(x)? (–2, 0) (0, –2) (2, –1) (4, 0)

Answer :

Thomas Thomas

Answer:

That would be the point(-2, -1)

Step-by-step explanation:

The graph rises between  (-3, -4) and (-2, -1)  then falls as it passes through the last 2 points ( y = -1 goes to y= -5 and then to y = -8 as x values move to the right).

Which is a possible turning point for the continuous function f(x)? (–2, 0) (0, –2) (2, –1) (4, 0)

Nicholasv0612 Nicholasv0612

Answer: (–2, 1)

Step-by-step explanation:

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    Video Transcript

    Hello, we have to determine function is containing a c f of x that is equals to x square minus 6 x upon x square plus 6 x. I x not equals to 0, and it is minus 14 x is equals to 0. So the value of the limit extends to 0 of f x, so this is equal to minus 6 upon 6, so this will be equals to minus 1 point. Okay and then for f of 0 is minus 1. So we can say that limit x, tends to 0 of f x, is equals to minus 1 equals to f of 0 point, so we can see that the function is continuous function. Is its continuous kai hope? You understood.

    Which is a possible turning point for the continuous function f(x)? (–2, 0) (0, –2) (2, –1) (4, 0)

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    Let $f$ be a continuous function with $f(0)=f(2)=0 .$ If the graph of $y=f^{\prime}(x)$ is as shown in Figure $14,$ sketch a possible graph for $y=f(x)$.

    Which is a possible turning point for the continuous function f(x)? (–2, 0) (0, –2) (2, –1) (4, 0)

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    Video Transcript

    Yeah. So given figure 14, we want to schedule possible graph for F. Of X. And we know that F. Of zero equals F to so f of zero equals effort to. They're both zero then. Um between one and three we see that there's going to be yes. Um Ask him to do it too. So we see that from negative to are at positive two we're going from a um positive to negative, so at this point it's going to be will be positive and then at one it goes negative and then we're going to see a sharp turn in the graph because it immediately goes positive like this. And then we see that there's also going to be an inflection point at one where it goes from increasing decreasing, but the graph is decreasing the whole time so it can be decreasing but concave down. So something like this perhaps

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