Latest Graphical Representation MCQ Objective Questions
Graphical Representation Question 1:
Study the following graph.
Total exports for the given year is:
- Rs 3800 crore
- Rs 3900 crore
- Rs 3700 crore
- Rs 4000 crore
Answer (Detailed Solution Below)
Option 2 : Rs 3900 crore
Calculation:
From the given data, we can see that,
Total exports = 300+ 200 + 600 + 450 + 600 + 800 + 950
⇒ Total exports = Rs. 3900 crore
Graphical Representation Question 2:
Bar chart shows production of cement by four factories A, B, C & D over the years
The production of cement by factory B in 2009 and production of cement by factory D in 2010 together is what percentage of percent of production by factory A in 2008 ?
- 100 %
- 191.67 %
- 300 %
- 400 %
Answer (Detailed Solution Below)
Option 2 : 191.67 %
Formula used:
Percentage = (Value/Total value) × 100
If A is x percentage of B, then
x % = (A/B) ×100
Calculation:
As shown in a bar chart,
Production of cement by factory B in 2009 and by factory D in 2010 together
= 50 + 65 = 120 lakh tonne
Production of cement by factory A in 2008 = 60 lakh tonne
Hence, the required percentage
\(=\ \frac{115}{60}\ × \ 100 \) = 191.67 %
Hence, option 2 is correct.
Graphical Representation Question 3:
The annual vehicles production (in lacs) in india is given in the pie chart.
If the annual production of motor cycle is 1.80 lacs, the annual production of Bicycle is
- 2.6 lacs
- 2.4 lacs
- 2.5 lacs
- 2.1 lacs
Answer (Detailed Solution Below)
Option 2 : 2.4 lacs
Calculation
Annual production of motor cyle = 1.80 lakh
⇒ 90° = 1.80
⇒ 1° = 0.02
⇒ 120° = 2.4 lacs
∴ The annual production of Bicycle is 2.4 lacs
Graphical Representation Question 4:
Following histogram shows certain frequency distribution against class intervals.
The approximated mean of this distribution is:
- 34.34
- 35.42
- 37.86
- 36
Answer (Detailed Solution Below)
Option 3 : 37.86
Formula
Mean = ∑fx/∑f
Calculation
Interval | Mid – point (x) | Frequency (f) | Fx |
10 – 20 | 15 | 8 | 120 |
20 – 30 | 25 | 20 | 500 |
30 – 40 | 35 | 16 | 560 |
40 – 50 | 45 | 24 | 1080 |
50 – 60 | 55 | 12 | 660 |
60 – 70 | 65 | 4 | 260 |
Total | 84 | 3180 |
⇒ Mean = 3180/84
∴ The Mean is 37.86 (approx)
Graphical Representation Question 5:
Which of the following is a method of collection of primary data?
- Direct personal interview
- Indirect personal interview
- Schedules through enumerators
- All of the options
Answer (Detailed Solution Below)
Option 4 : All of the options
Explanation
We can collect the primary data from direct personal interview, indirect personal interview and schedules through enumerators
∴ All options are correct
Top Graphical Representation MCQ Objective Questions
For determination of mode and median graphically, one considers:
- Bar diagram and Ogive
- Bar diagram and Line diagram
- Histogram and Line diagram
- Histogram and Ogive
Answer (Detailed Solution Below)
Option 4 : Histogram and Ogive
Explanation
In the determination of median graphically we adopt any of the two methods. In both the methods we draw ogives as per requirement.
To calculate mode graphically a histogram of the given data is drawn at first.
∴ For determination of mode and median graphically, one considers Histogram and Ogive
Bar diagram = A bar chart or bar graph is a chart or graph that presents categorical data with rectangular bars with heights or lengths proportional to the values that they represent.
We can represent Mean on Bar graph
Ogive = An ogive (oh-jive), sometimes called a cumulative frequency polygon, is a type of frequency polygon that shows cumulative frequencies. In other words, the cumulative percents are added on the graph from left to right.
We represent partition value on ogive curve like median
Line graph = line graph is a type of chart used to show information that changes over time. We plot line graphs using several points connected by straight lines. We also call it a line chart
If computers and monitors are set in ‘sleep’ mode when not in use, the energy cost is reduced approximately by:
- 25 percent
- 45 percent
- 30 percent
- 40 percent
Answer (Detailed Solution Below)
Option 4 : 40 percent
Screen savers do not reduce the use of power by your computer; once your screen saver kicks in, your monitor will draw its full power load.
All users, whether on desktops or laptops, should configure their computers to use the power-saving or energy star modes that shut down power to the monitor, hard drive, and computer itself after periods of inactivity.
Putting your computer in sleep mode allows it to use substantially less power, allows it to respond to some types of network activity, and allows you to not power off the computer.
A computer display in full use gobbles up 65 watts – but still uses 25 watts when in sleep mode. When off it uses 0.8 watts.
Setting computers, monitors, and copiers to use sleep-mode when not in use helps cut energy costs by approximately 40%.
The numbers of Science, Arts and Commerce graduates working in a company are 30, 70 and 50 respectively. If these figures are represented by a pie chart, then what is the angle corresponding to Science graduates?
- 36°
- 72°
- 120°
- 168°
Answer (Detailed Solution Below)
Option 2 : 72°
Concept:
In a pie chart, the central angle of each slice of the pie is proportional to its value as compared to the total value.
θ = \(\rm \frac{\text{Value of Slice.}}{\text{Total Value.}}\times360^\circ\)
Calculation:
Angle corresponding to the Science graduates = θ = \(\rm \frac{\text{Number of Science graduates.}}{\text{Total number of graduates.}}\times360^\circ\).
= \(\rm \frac{30}{30+70+50}\times360^\circ\)
= \(\rm \frac{30}{150}\times360^\circ\)
= 72°.
In an examination, 40% of candidates got second class. When the data are represented by a pie chart, what is the angle corresponding to second class?
- 40°
- 90°
- 144°
- 320°
Answer (Detailed Solution Below)
Option 3 : 144°
Calculation:
Let the circle be the total number of students.
Therefore 100% = 360°
⇒ 1% = \(\frac{{360^\circ }}{{100}}\)
\(\therefore \;40\% \; = \frac{{360^\circ }}{{100}} \times 40 = 144^\circ\)
For a histogram based on a frequency distribution with unequal class intervals, the frequency of a class should be proportional to:
- the height of the rectangle.
- the area of the rectangle.
- the width of the rectangle.
- the perimeter of the rectangle.
Answer (Detailed Solution Below)
Option 2 : the area of the rectangle.
Concept:
- When constructing a histogram with non-uniform (unequal) class widths, we must ensure that the areas of the rectangles are proportional to the class frequencies.
- Remember that the histogram differs from a bar chart in that it is the area of the bar that denotes the value, not the height. This means that we would need to consider the widths in order to determine the height of each rectangle.
Calculation:
From the definition of histogram, it is clear that the frequency of a class is proportional to the area of the rectangle, and NOT to its height.
For how many days were the number of road accident patients treated less than 4?
Number of road accidents patients treated by a hospital emergency ward for 120 days are given below: | ||||||||
Number of patients | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Days | 11 | 16 | 21 | 23 | 20 | 17 | 7 | 5 |
- 71
- 48
- 69
- 46
Answer (Detailed Solution Below)
Option 1 : 71
Calculation
No. off patient | Days |
0 | 11 |
1 | 16 |
2 | 21 |
3 | 23 |
4 | 20 |
5 | 17 |
6 | 7 |
7 | 5 |
the number of road accident patients treated less than 4 = 11 + 16 + 21 + 23 = 71
Ogives can be helpful in locating graphically the
- Mode
- Mean
- Median
- None of the above
Answer (Detailed Solution Below)
Option 3 : Median
Explanation:
Graphically, the median can be determined by the intersection point of Less than Ogive and More than Ogive.
The value of the x-axis corresponding to the intersection point indicates the median.
Hence, option (3) is correct.
Ogives - To find median
Histogram - To find mode
Following histogram shows certain frequency distribution against class intervals.
The approximated mean of this distribution is:
- 34.34
- 35.42
- 37.86
- 36
Answer (Detailed Solution Below)
Option 3 : 37.86
Formula
Mean = ∑fx/∑f
Calculation
Interval | Mid – point (x) | Frequency (f) | Fx |
10 – 20 | 15 | 8 | 120 |
20 – 30 | 25 | 20 | 500 |
30 – 40 | 35 | 16 | 560 |
40 – 50 | 45 | 24 | 1080 |
50 – 60 | 55 | 12 | 660 |
60 – 70 | 65 | 4 | 260 |
Total | 84 | 3180 |
⇒ Mean = 3180/84
∴ The Mean is 37.86 (approx)
The monthly family expenditure (in percentage) on different items are as follows:
Food | Rent | Cloth | Transport | Education | Others |
38 | 19 | 18 | - | 9 | 6 |
If the total monthly expenditure is Rs. 9000, then what is the expenditure on transport?
- Rs. 180
- Rs. 1000
- Rs. 900
- Rs. 360
Answer (Detailed Solution Below)
Option 3 : Rs. 900
Calculation:
Let the monthly percentage of expenditure on transport be x%
Consider, total monthly family expenditure = 100%
⇒ 38 + 19 + 18 + x + 9 + 6 = 100
⇒ x = 10
Now, expenditure on transport = \(\rm \frac {x}{100} \times 9000\)
\(=\rm \frac {10}{100} \times 9000\) = Rs. 900
In a pie chart depicting total expenses of a company for the year 2016, raw material had a central angle of 45o. If total expenses were Rs 504 Lakhs, what were the company's expense on raw materials (in Rs lakhs)?
- 45
- 112
- 63
- 72
Answer (Detailed Solution Below)
Option 3 : 63
Given
Total expenses = 504 lakhs
Raw material had a central angle 45°
Concept used
In the pie chart overall angle is 360°
Calculation
The total expenses = 504 lakhs
⇒ 360° = 504 lakhs
⇒ 1° = 1.4 lakh
⇒ 45° = 63 lakh
∴ the company's expense on raw materials (in Rs lakhs) - is 63 lakhs