probability heads tosses fair coin Getting two tails

What is the probability of getting exactly 2 heads in 6 tosses of a fair coin?

1.
TTHHHH
like this we can write in C(6,2) ways =15
therefore n(A)=15
n(S)=2^6 =64
finally P(A) =15/64
2.
Sum of 16 can be achieved in following ways
6,6,4---Total cases = 3!/2! = 3
6,5,1---Total cases = 3!= 6
Total cases = 6+3=9
Probability = 9* (1/6 * 1/6 * 1/6) = 9/216

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Updated On: 27-06-2022

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Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

What is the probability of getting exactly 2 heads in 6 tosses of a fair coin?

1.
TTHHHH
like this we can write in C(6,2) ways =15
therefore n(A)=15
n(S)=2^6 =64
finally P(A) =15/64
2.
Sum of 16 can be achieved in following ways
6,6,4---Total cases = 3!/2! = 3
6,5,1---Total cases = 3!= 6
Total cases = 6+3=9
Probability = 9* (1/6 * 1/6 * 1/6) = 9/216

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Neuester Beitrag

Stichworte

1. TTHHHH like this we can write in C(6,2) ways =15 therefore n(A)=15 n(S)=2^6 =64 finally P(A) =15/64 2. Sum of 16 can be achieved in following ways 6,6,4---Total cases = 3!/2! = 3 6,5,1---Total cases = 3!= 6 Total cases = 6+3=9 Probability = 9* (1/6 * 1/6 * 1/6) = 9/216

Related Videos

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zusammenhängende Posts

Toplist

Neuester Beitrag

Stichworte

1.
TTHHHH
like this we can write in C(6,2) ways =15
therefore n(A)=15
n(S)=2^6 =64
finally P(A) =15/64
2.
Sum of 16 can be achieved in following ways
6,6,4---Total cases = 3!/2! = 3
6,5,1---Total cases = 3!= 6
Total cases = 6+3=9
Probability = 9* (1/6 * 1/6 * 1/6) = 9/216